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Question: Two rods, one of aluminum and the other made of steel, having initial length \(l_{1}\) and \(l_{2}\)...

Two rods, one of aluminum and the other made of steel, having initial length l1l_{1} and l2l_{2} are connected together to form a single rod of length l1+l2l_{1} + l_{2}.

The coefficients of linear expansion for aluminum and steel are αa\alpha_{a} and αs\alpha_{s} respectively. If the length of each rod increases by the same amount when their temperature are raised by toCt^{o}C, then find the ratio l1(l1+l2)\frac{l_{1}}{(l_{1} + l_{2})}

A

αsαa\frac{\alpha_{s}}{\alpha_{a}}

B

αaαs\frac{\alpha_{a}}{\alpha_{s}}

C

αs(αa+αs)\frac{\alpha_{s}}{(\alpha_{a} + \alpha_{s})}

D

αa(αa+αs)\frac{\alpha_{a}}{(\alpha_{a} + \alpha_{s})}

Answer

αs(αa+αs)\frac{\alpha_{s}}{(\alpha_{a} + \alpha_{s})}

Explanation

Solution

Given Δl1=Δl2\Delta l_{1} = \Delta l_{2} or l1αat=l2αstl_{1}\alpha_{a}t = l_{2}\alpha_{s}t

\therefore l1l2=αsαa\frac{l_{1}}{l_{2}} = \frac{\alpha_{s}}{\alpha_{a}} or l1l1+l2=αsαa+αs\frac{l_{1}}{l_{1} + l_{2}} = \frac{\alpha_{s}}{\alpha_{a} + \alpha_{s}}.