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Question: Two rods, one of aluminum and other of steel, having initial lengths \( {l_1} \) and \( {l_2} \) are...

Two rods, one of aluminum and other of steel, having initial lengths l1{l_1} and l2{l_2} are connected together to form a single rod of length l1+l2{l_1} + {l_2} . The coefficients of linear expansion of aluminium and steel are αA{\alpha _A} and αS{\alpha _S} respectively. It the length of each rod increases by same amount when the temperature is raised by t0C{t^0}C then find the relation l1l1+l2\dfrac{{{l_1}}}{{{l_1} + {l_2}}} .
(A) αAαA+αS\dfrac{{{\alpha _A}}}{{{\alpha _A} + {\alpha _S}}}
(B) αSαA\dfrac{{{\alpha _S}}}{{{\alpha _A}}}
(C) αAαS\dfrac{{{\alpha _A}}}{{{\alpha _S}}}
(D) αSαA+αS\dfrac{{{\alpha _S}}}{{{\alpha _A} + {\alpha _S}}}

Explanation

Solution

Hint : Aluminum and steel are the alloys and can be used to make utensils or rods. The rod has initial lengths and coefficient of linear expansion. These both are inversely proportional to each other. The length can be increased by the increase in temperature.

Complete Step By Step Answer:
Given that two rods are there. One is made of aluminum and another rod is made up of steel. The aluminum rod has the initial length of l1{l_1} and the steel rod has the initial length of l2{l_2} . The aluminium rod has the coefficient of linear expansion of αA{\alpha _A} and the steel rod has the coefficient of linear expansion of αS{\alpha _S} .
The lengths and coefficient of linear expansion.
Thus, the relation will be
l2l1=αAαS\dfrac{{{l_2}}}{{{l_1}}} = \dfrac{{{\alpha _A}}}{{{\alpha _S}}}
Addition of 11 on both sides, we will get
1+l2l1=1+αAαS1 + \dfrac{{{l_2}}}{{{l_1}}} = 1 + \dfrac{{{\alpha _A}}}{{{\alpha _S}}}
By simplification, the relation will be
l1+l2l1=αA+αSαS\dfrac{{{l_1} + {l_2}}}{{{l_1}}} = \dfrac{{{\alpha _A} + {\alpha _S}}}{{{\alpha _S}}}
The inverse of the above relation is
l1l1+l2=αSαA+αS\dfrac{{{l_1}}}{{{l_1} + {l_2}}} = \dfrac{{{\alpha _S}}}{{{\alpha _A} + {\alpha _S}}}
Thus, l1l1+l2\dfrac{{{l_1}}}{{{l_1} + {l_2}}} is equal to the αSαA+αS\dfrac{{{\alpha _S}}}{{{\alpha _A} + {\alpha _S}}} .
Option D is the correct one.

Note :
Alloy is a mixture of two or more chemical elements prepared mainly for the resistivity of corrosion. Steel is an alloy of iron and carbon. Stainless steel has a different composition than steel. The rods of alloy or metals expand in only direction along the length can be called as linear expansion.