Question
Physics Question on Current electricity
Two resistors of resistances R1=(300±3)Ω and R2=(500±4)Ω are connected in series. The equivalent resistance of the series combination is
A
(800±1)Ω
B
(800±7)Ω
C
(200±7)Ω
D
(200±1)Ω
Answer
(800±7)Ω
Explanation
Solution
The equivalent resistance of series combination is Rs=R1+R2=300Ω+500Ω=800Ω The error in equivalent resistance is given by ΔR=(ΔR1+ΔR2)=(3+4)Ω=7Ω Hence, the equivalent resistance along with error is (800±7)Ω.