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Question

Physics Question on Current electricity

Two resistors of resistances 200kΩ200\,k\Omega and 1MΩ1\,M\Omega respectively form a potential divider with outer junctions maintained at potentials of +3V+3V and 15V-15V . Then, the potential at the junction between the resistors is

A

+1 V+1\text{ }V

B

0.6 V-0.6\text{ }V

C

zero

D

12V-\,12V

Answer

zero

Explanation

Solution

Current i=V1V2R1+R2=181.2×106i=\frac{{{V}_{1}}-{{V}_{2}}}{{{R}_{1}}+{{R}_{2}}}=\frac{18}{1.2\times {{10}^{-6}}}
V across 1MΩ=181.2×106×1×1061\,M\Omega =\frac{18}{1.2\times {{10}^{-6}}}\times 1\times {{10}^{-6}}
=15V=15\,V
\therefore Potential at P=1515=0P=15-15=0