Question: Two resistors of $6\Omega$ and $9\Omega$ are connected in series to a 120 volt source. The power...

Question

Two resistors of $6\Omega$ and $9\Omega$ are connected in series to a 120 volt source. The power consumed by the $6\Omega$ resistor is

Answer 1

Current through the combination $i = \frac{120}{(6 + 9)} = 8A$

So, power consumed by 6 Ω resistance

$P = (8)^{2} \times 6 = 384W$

Question: Two resistors of \(6\Omega\) and \(9\Omega\) are connected in series to a 120 volt source. The power...