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Question: Two resistors are connected (1) in series (2) in parallel. The equivalent resistance in the two case...

Two resistors are connected (1) in series (2) in parallel. The equivalent resistance in the two cases are 9ohmohm and 2ohmohm respectively. Then the resistances of the component resistors are

A

2ohmohm and 7ohmohm

B

3ohmohm and 6ohmohm

C

3ohmohm and 9ohmohm

D

5ohmohm and 4ohmohm

Answer

3ohmohm and 6ohmohm

Explanation

Solution

R1+R2=9R_{1} + R_{2} = 9 and R1R2R1+R2=2\frac{R_{1}R_{2}}{R_{1} + R_{2}} = 2R1R2=18R_{1}R_{2} = 18

R1R2=(R1+R2)24R1R2=8172=3R_{1} - R_{2} = \sqrt{(R_{1} + R_{2})^{2} - 4R_{1}R_{2}} = \sqrt{81 - 72} = 3

R1=6Ω,R2=3ΩR_{1} = 6\Omega,R_{2} = 3\Omega