Question

Two resistances of 100 $\Omega$ and 200 $\Omega$ are connected in series across a 20 V battery as shown in the figure below. The reading in a 200 $\Omega$ voltmeter connected across the 200 $\Omega$ esistance is _______.

Fill in the blank with the correct answer from the options given below

• A. 4V
• B. $\frac{20}{3}V$
• C. 10V
• D. 16V

Answer 1

Answer: (B)

$\frac{20}{3}V$

Answer 2

The resistances are in series, so the total resistance is $R_{total}=100\Omega+200\Omega=300\Omega$
The current in the circuit is $I=\frac{200}{300}=\frac{1}{15}A$
The voltage across the $200\Omega$ resistance is $V=IR=\frac{1}{15}\times200=\frac{200}{15}=\frac{20}{3}V$