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Question

Physics Question on Thermodynamics

Two rectangular blocks, having identical dimensions, can be arranged either in configuration I or in configuration II as shown in the figure. One of the blocks has thermal conductivity κ\kappa and the other 2κ.2 \,\kappa . The temperature difference between the ends along the xx-axis is the same in both the configurations. It takes 9s9\, s to transport a certain amount of heat from the hot end to the cold end in the configuration I. The time to transport the same amount of heat in the configuration II is

A

2.0 s

B

3.0 s

C

4.5 s

D

6.0 s

Answer

2.0 s

Explanation

Solution

R1=LκA+L2κA=3L2κAR _{1}=\frac{ L }{ \kappa A }+\frac{ L }{2 \kappa A }=\frac{3 L }{2 \kappa A }
1R2=1(LKA)+1(L2κA)=3κAL\frac{1}{ R _{2}}=\frac{1}{\left(\frac{ L }{ K A }\right)}+\frac{1}{\left(\frac{ L }{2 \kappa A }\right)}=\frac{3 \kappa A }{ L }
R2=L3κAR _{2}=\frac{ L }{3 \kappa A }
ΔQ1=ΔQ2\Delta Q _{1}=\Delta Q _{2}
ΔTR1t1=ΔTR2t2\frac{\Delta T }{ R _{1}} t _{1}=\frac{\Delta T }{ R _{2}} t _{2}
t2=R2R1t1\Rightarrow t _{2}=\frac{ R _{2}}{ R _{1}} t _{1}
=2sec=2 \,\sec