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Question: Two rectangular blocks A and B of different metals have same length and same area of cross-section. ...

Two rectangular blocks A and B of different metals have same length and same area of cross-section. They are kept in such a way that their cross-sectional area touch each other. The temperature at one end of A is 100°C and that of B at the other end is 0°C. If the ratio of their thermal conductivity is 1 : 3, then under steady state, the temperature of the junction in contact will be

A

25°C

B

50°C

C

75°C

D

100°C

Answer

25°C

Explanation

Solution

It is given that K1K2=13\frac { K _ { 1 } } { K _ { 2 } } = \frac { 1 } { 3 }K1=KK _ { 1 } = K then K2=3KK _ { 2 } = 3 K the temperature of the junction in contact

θ=K1θ1+K2θ2K1+K2\theta = \frac { K _ { 1 } \theta _ { 1 } + K _ { 2 } \theta _ { 2 } } { K _ { 1 } + K _ { 2 } } =1×100+3×01+3=1004= \frac { 1 \times 100 + 3 \times 0 } { 1 + 3 } = \frac { 100 } { 4 }= 25°C