Question
Question: Two reactions A ¾® products and B ¾® products have rate constant, k<sub>a</sub> and k<sub>b</sub> re...
Two reactions A ¾® products and B ¾® products have rate constant, ka and kb respectively at temperature T and activation energies are Ea and Eb respectively.
If ka> kb and Ea<Eb and assuming the frequency factor A in both the reactions are same then
A
On increasing temperature ka will be greater than kb
B
At lower temperature ka and kb will differ more
C
As temperature rises ka and kb will be close to each other
in magnitude
D
All of the above are correct
Answer
All of the above are correct
Explanation
Solution
ln ka = A – Ea/RT ; ln kb = A – Eb/RT
As temperature rises E/RT become negligible