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Question: Two rays travelling parallel to the principal axis strike a large plano-convex lens having a refract...

Two rays travelling parallel to the principal axis strike a large plano-convex lens having a refractive index of 1.60. If the convex face is spherical, a ray near the edge does not pass through the focal point (spherical aberration). If this face has a radius of curvature of 20.0 cm & the two rays are h1 = 0.5 cm & h2 = 12.0 cm from the principal axis, find the difference in the positions where they cross the principal axis –

A

42.6 cm

B

21.3 cm

C

10.6 cm

D

11.3 cm

Answer

21.3 cm

Explanation

Solution

1.60 sin i = sin r

1.60×hR\frac { 1.60 \times h } { R } = sin r

hPF=tan(ri)\frac { \mathrm { h } } { \mathrm { PF } } = \tan ( \mathrm { r } - \mathrm { i } )

in this way we can calculate PF for both rays and difference in position = PF2 – PF1