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Question: Two radioactive samples have decay constant 15x and 3x. If they have same number of nuclei initially...

Two radioactive samples have decay constant 15x and 3x. If they have same number of nuclei initially, the ratio of number of nuclei after a time 16x\dfrac {1}{6x} is

Explanation

Solution

To solve this problem, use the formula for number of nuclei at time t. Using the formula, find the number of nuclei at time 16x\dfrac {1}{6x} for both the radioactive samples. Then, take the ratio of the number of nuclei at time 16x\dfrac {1}{6x} for the first sample to the number of nuclei at time 16x\dfrac {1}{6x} for the second sample. This will give the ratio of the number of nuclei after a time 16x\dfrac {1}{6x}.
Formula used:
N=N0eλtN= {N}_{0}{e}^{- \lambda t}

Complete answer:
Given: Decay constant of first sample (λ1{\lambda}_{1})= 15x
Decay constant of second sample (λ2{\lambda}_{2})= 3x
The number of nuclei at time t is given by,
N=N0eλtN= {N}_{0}{e}^{- \lambda t}
Where, N0{N}_{0} is the number of nuclei at t=0
t is the time
λ\lambda is the decay constant
The number of nuclei at time 16x\dfrac {1}{6x} for first sample is given by,
N1=N0eλ1t{N}_{1}= {N}_{0}{e}^{- {\lambda}_{1} t}
Substituting values in above equation we get,
N1=N0e15x16{N}_{1}= {N}_{0}{e}^{-\dfrac {15x}{16}}
N1=N0e2.5x\Rightarrow {N}_{1}= {N}_{0}{e}^{-2.5x} ...(1)
Similarly, the number of nuclei at time 16x\dfrac {1}{6x} for second sample is given by,
N2=N0eλ2t{N}_{2}= {N}_{0}{e}^{- {\lambda}_{2} t}
Substituting values in above equation we get,
N2=N0e3x16{N}_{2}= {N}_{0}{e}^{-\dfrac {3x}{16}}
N2=N0e0.5x\Rightarrow {N}_{2}= {N}_{0}{e}^{-0.5x}N ...(2)
Now, taking the ratio of equations. (1) and (2) we get,
N=N1N2N= \dfrac {{N}_{1}}{{N}_{2}}
Substituting values in above equation we get,
N=N0e2.5xN0e0.5xN= \dfrac {{N}_{0}{e}^{-2.5x}}{{N}_{0}{e}^{-0.5x}}
N=e2.5xe0.4x\Rightarrow N= \dfrac {{e}^{-2.5x}}{{e}^{-0.4x}}
N=e2.5×e0.5\Rightarrow N= {e}^{-2.5} \times {e}^{0.5}
N=e2\Rightarrow N= {e}^{-2}
N=1e2\therefore N= \dfrac {1}{{e}^{2}}
Hence, the ratio of the number of nuclei after a time 16x\dfrac {1}{6x} is 1e2 \dfrac {1}{{e}^{2}}.

Note:
In order to solve such types of problems, students must remember the basic definition and these relations. Decay constant is the reciprocal of time during which the number of nuclei of a radioactive substance decreases to 1e\dfrac {1}{e} or 36.8% of the initial number of nuclei. The decay constant varies for different types of nuclei. Decay constant depends upon various environmental factors such as temperature, pressure etc.