Solveeit Logo

Question

Physics Question on laws of motion

Two pulley arrangements (A) and (B) are as shown in the figure. Neglect the masses of the ropes and pulleys and the friction at the axle of the pulleys. The ratio of the acceleration of mass m in arrangement (A) to that in arrangement (B) is

A

1:01

B

1:02

C

1:03

D

2:15

Answer

1:03

Explanation

Solution

In case AA, the acceleration of mass mm is a=(2mm)gm+2m=g3a=\frac{\left(2m-m\right)g}{m+2m}=\frac{g}{3} In case BB, the acceleration of mass mm is a=2mgmgm=gaa=13a'=\frac{2mg-mg}{m}=g\,\therefore \frac{a}{a'}=\frac{1}{3}