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Question

Physics Question on projectile motion

Two projectiles thrown at 30° and 45° with the horizontal, respectively, reach the maximum height in same time. The ratio of their initial velocities is :

A

1:21:\sqrt 2

B

2:12:1

C

2:1\sqrt 2:1

D

1:21:2

Answer

2:1\sqrt 2:1

Explanation

Solution

We know that,
ta=u sin⁡ θgt_a=\frac {u\ sin⁡\ θ}{g}

u1sin(30)g=u2sin(45)g⇒\frac {u_1sin⁡(30^∘)}{g}=\frac {u_2sin⁡(45^∘)}{g}
The ratio of their initial velocities is:
u1u2=1212⇒\frac {u_1}{u_2}=\frac {\frac {1}{\sqrt 2}}{\frac 12}

u1u2=21⇒\frac {u_1}{u_2}=\frac {\sqrt 2}{1}

So, the correct option is (C): 2:1\sqrt 2:1