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Question

Physics Question on Polarisation

Two polaroids AA and BB are placed with their polaroid axes 3030^{\circ} to each other as shown in the figure. A plane polarized light passes through the polaroid AA and after passing through it, intensity of light becomes I0I_0.What is the intensity of finally transmitted light after passing through the polaroid BB ?

A

0.25I00.25I_0

B

0.5I00.5I_0

C

0.75I00.75I_0

D

0.866I00.866I_0

Answer

0.75I00.75I_0

Explanation

Solution

The intensity / of the transmitted light varies directly as the square of the cosine of the angle between the transmission direction of polariser and analyser
I=I0cos2θI=I_{0} \cos ^{2} \theta
Intensity of finally transmitted light after passing through polaroid BB is given by I=I0cos2θI=I_{0} \cos ^{2} \theta (Intensity)
I=I0cos230I=I_{0} \cdot \cos ^{2} 30^{\circ}
I=I00.75I=I_{0} 0.75
I=0.75I0I=0.75 I_{0}
where, I0I_{0} is the maximum intensity of transmitted light.