Question

Two points separated by a distance of 0.1 mm can just be resolved in a microscope when a light of wavelength 6000 Å is used. If the light of wavelength 4800 Å is used this limit of resolution becomes

• A. 0.08 mm
• B. 0.10 mm
• C. 0.12 mm
• D. 0.06 mm

Answer 1

Answer: (A)

0.08 mm

Answer 2

By using resolving limit (R.L.) ∝ λ ⇒ $\frac{(R.L.)_{1}}{(R.L.)_{2}} = \frac{\lambda_{1}}{\lambda_{2}}$

⇒ $\frac{0.1}{(R.L.)_{2}} = \frac{6000}{4800}$ ⇒ $(R.L.)_{2} = 0.08mm$.