Question

Two points A and B are located in diametrically opposite directions of a point charge of $+ 2\mu C$at distances 2 m and 1 m respectively from it. The potential difference between A and B is.

• A. $3 \times 10^{3}V$
• B. $6 \times 10^{4}V$
• C. $- 9 \times 10^{3}V$
• D. $- 3 \times 10^{3}V$

Answer 1

Answer: (C)

$- 9 \times 10^{3}V$

Answer 2

: Here, $q = 2\mu C = 2 \times 10^{- 6}C,$

$r_{A} = 2m,r_{B} = 1m$

$\therefore V_{A} - V_{B} = \frac{q}{4\pi\varepsilon_{0}}\left\lbrack \frac{1}{r_{A}} - \frac{1}{r_{B}} \right\rbrack$

$= 2 \times 10^{- 6} \times 9 \times 10^{9}\left\lbrack \frac{1}{2} - \frac{1}{1} \right\rbrack V$

$= - 9 \times 10^{3}V$