Question

Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of 10 kg-m/s is given to the 5 kg mass. The velocity of the 10 kg mass will be –

• A. $\frac { 2 } { 3 }$ m/s
• B. $\frac { 1 } { 3 }$ m/s
• C. 2 m/s
• D. Zero

Answer 1

Answer: (B)

$\frac { 1 } { 3 }$ m/s

Answer 2

Apply impulse equation, along string

10 Ч $\frac { 1 } { 2 }$ = (10 + 5)

[v = $\frac { 1 } { 3 }$m/s]