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Question: Two point like charges of same magnitude but opposite signs are fixed to either end of the base of a...

Two point like charges of same magnitude but opposite signs are fixed to either end of the base of an isosceles triangle as figure shows. The electric field intensity at the midpoint M between the charge has a magnitude EM. The electric field intensity directly above the midpoint at point P has magnitude EP. The ratio of these two field magnitude is EM : EP = 27. Find the value of cosa

A

13\frac{1}{3}

B

16\frac{1}{6}

C

12\frac{1}{2}

D

19\frac{1}{9}

Answer

13\frac{1}{3}

Explanation

Solution

EM = kq×2r2cos2α\frac { \mathrm { kq } \times 2 } { \mathrm { r } ^ { 2 } \cos ^ { 2 } \alpha }

EP =

= 1cos3α\frac { 1 } { \cos ^ { 3 } \alpha } = 27

cos a = (127)1/3\left( \frac { 1 } { 27 } \right) ^ { 1 / 3 } ̃ cos a = 1/3