Physics Question on Electrostatic potential

Question

Two point charges $- Q$ and $\frac{+ Q }{ \sqrt{3}}$ are placed in the $xy$ -plane at the origin $(0,0)$ and a point $(2,0)$ , respectively, as shown in the figure. This results in an equipotential circle of radius $R$ and potential $V=0$ in the $x y$ -plane with its center at $(b, 0)$ . All lengths are measured in meters
Two point charges −𝑄 and +𝑄/√3 are placed in the xy-plane at the origin 0, 0 and a point 2, 0, respectively, as shown in the figure. This results in an equipotential circle of radius 𝑅 and potential 𝑉 = 0 in the xy-plane with its center at b, 0. All lengths are measured in meters.