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Question

Physics Question on Electric Field

Two point charges QQ and 3Q-3Q are placed certain distance apart. If the electric field at the location of QQ be E\overrightarrow{E}, then that at the location of 3Q-3Q will be :

A

3E3\,\overrightarrow{E}

B

3E-3\,\overrightarrow{E}

C

E/3\overrightarrow{E}/3

D

E/3-\overrightarrow{E}/3

Answer

3E-3\,\overrightarrow{E}

Explanation

Solution

Given, point charges: QQ and 3Q-3 Q electric field at Q=EQ=\vec{E} Let the electric field around QQ ? And electric fidd around 3Q=E2-3 Q=E_{2}. E1=RQr2=Eˉ[r=smallaround Qdistance ]E_{1}=\frac{R Q}{r^{2}}=\bar{E} \quad\left[r=\operatorname{small}_{\text {around }} Q_{\text {distance }}\right] \text {. } similarly, E2=k(3Q)r2 =3kQr2=(3)[kQr2]. E2=3E\begin{aligned} E_{2} &=\frac{k(-3 Q)}{r^{2}} \\\ &=\frac{-3 k Q}{r^{2}}=(-3)\left[\frac{k Q}{r^{2}}\right] . \\\ E_{2} &=-3 \vec{E} \end{aligned} Thus, the electric field at location of 3Q-3 Q charge will be 3E-3 \vec{E}.