Question: Two point charges of $20\mu C$ and $80\mu C$ are $10cm$ apart. Where will the electric field s...

Question

Two point charges of $20\mu C$ and $80\mu C$ are $10cm$ apart. Where will the electric field strength be zero on the line joining the charges from $20\mu C$ charge

Answer 1

Solution

Let neutral point be obtained at a distance x from 20 μC charge. Hence at neutral point

$\frac{20}{(x)^{2}} = \frac{80}{(10 - x)^{2}}$ ⇒ $x = + 0.033m$

Question: Two point charges of \(20\mu C\) and \(80\mu C\) are \(10cm\) apart. Where will the electric field s...

Solution