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Question: Two point charges \(+ 3\mu C\)and \(+ 8\mu C\) repel each other with a force of 40 N. If a charge of...

Two point charges +3μC+ 3\mu Cand +8μC+ 8\mu C repel each other with a force of 40 N. If a charge of5μC- 5\mu C is added to each of them, then the force between them will become

A

10N- 10N

B

+10N+ 10N

C

+20N+ 20N

D

20N- 20N

Answer

10N- 10N

Explanation

Solution

Initially F=k×3×8×1012r2F = k \times \frac{3 \times 8 \times 10^{- 12}}{r^{2}} and Finally

F=k2×3×1012r2F' = - k\frac{2 \times 3 \times 10^{- 12}}{r^{2}} so FF=14\frac{F'}{F} = - \frac{1}{4}F=10NF' = - 10N