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Question: Two plates of same thickness, of coefficients of thermal conductivity K<sub>1</sub> and K<sub>2</sub...

Two plates of same thickness, of coefficients of thermal conductivity K1 and K2 and areas of cross-section A1 and A2, are connected as shown ; the common coefficient of thermal conductivity K will be –

A

K1A1 + K2A2

B

K1A1+K2A2A1+A2\frac{K_{1}A_{1} + K_{2}A_{2}}{A_{1} + A_{2}}

C

K1A2+K2A1A1+A2\frac{K_{1}A_{2} + K_{2}A_{1}}{A_{1} + A_{2}}

D

K1A1K2A2\frac{K_{1}A_{1}}{K_{2}A_{2}}

Answer

K1A1+K2A2A1+A2\frac{K_{1}A_{1} + K_{2}A_{2}}{A_{1} + A_{2}}

Explanation

Solution

KP = K1A1+K2A2K1+K2\frac{K_{1}A_{1} + K_{2}A_{2}}{K_{1} + K_{2}}