Question

Two plates are $2cm$ apart, a potential difference of$10\mspace{6mu} volt$ is applied between them, the electric field between the plates is

• A. $20\mspace{6mu} N/C$
• B. $500N/C$
• C. $5N/C$
• D. $250\mspace{6mu} N/C$

Answer 1

Answer: (B)

$500N/C$

Answer 2

$E = \frac{V}{d} = \frac{10}{2 \times 10^{- 2}} = 500N/C$