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Question: Two pipes A and B can fill a water tank in 20 minutes and 24 minutes, respectively, and the third pi...

Two pipes A and B can fill a water tank in 20 minutes and 24 minutes, respectively, and the third pipe C can empty at the rate of 3 gallons per minute. If A, B and C opened together, fill the tank in 15 minutes the capacity ( in gallons) of the tank is:
A. 180
B. 150
C. 120
D. 60

Explanation

Solution

Hint: Assume the capacity of the tank to be x gallon. Using a unitary method to calculate rate of A and rate of B as (A+B+C) together can fill the tank in 15 minutes, rate of (A+B+C) will be x15\dfrac{x}{15} gallons per minute. Put the values of the rate of A, B and C to get an equation in x and then solve the obtained equation to get the value of x.

Complete step-by-step answer:
Let us assume the capacity of the tank to be x gallons.
According to question, A fills the tank in 20 minutes i.e. A fills x gallons in 20 minutes. So, rate of A to fill =(x20)=\left( \dfrac{x}{20} \right) gallons per minute………………….(1)
According to the question, B fills the tank in 24 minutes. i.e. B fills x gallons in 24 minutes So, the rate of B to fill =(x24)=\left( \dfrac{x}{24} \right) gallons per minute……………. (2)
And, according to the question, when A, B and C can open together the tank gets filled in 15 minutes.
i.e. (A+B+C) fills x gallons in 15 minutes. So, the rate of (A+B+C) to fill =x15\dfrac{x}{15} gallons per minute.
(Rate of A)+(Rate of B)+(Rate of C)=x15\Rightarrow \left( \text{Rate of A} \right)+\left( \text{Rate of B} \right)+\left( \text{Rate of C} \right)=\dfrac{x}{15} .
Using eq (1) and (2), we will get,
x20+x24+(Rate of C)=x15\Rightarrow \dfrac{x}{20}+\dfrac{x}{24}+\left( \text{Rate of C} \right)=\dfrac{x}{15} .
According to the question, C can empty at a rate of 3 gallons per minute. So,
x20+x243=x15\Rightarrow \dfrac{x}{20}+\dfrac{x}{24}-3=\dfrac{x}{15} .
Taking terms containing ‘x’ to LHS and constant term to RHS, we will get,
x20+x24x15=3\Rightarrow \dfrac{x}{20}+\dfrac{x}{24}-\dfrac{x}{15}=3
Taking LCM in LHS, we will get,
6x+5x8x120=3\dfrac{6x+5x-8x}{120}=3 .
3x100=3\Rightarrow \dfrac{3x}{100}=3
On dividing both sides by 3, we will get,
x120=1\Rightarrow \dfrac{x}{120}=1 .
Multiplying both sides by 120, we will get,
x=120\Rightarrow x=120 .
Hence the required capacity of the tank is 120 gallons and option (c) is the correct answer.

Note: In the equation (Rate of A)+(Rate of B)+(Rate of C)=x15\left( \text{Rate of A} \right)+\left( \text{Rate of B} \right)+\left( \text{Rate of C} \right)=\dfrac{x}{15} , we have put rate of c=3c=-3. We have used negative signs because ‘C’ is making the tank empty while A and B are filling the tank.