Solveeit Logo
Login

Question

Chemistry Question on Molecular Orbital Theory

Two pi and half sigma bonds are present in:

A

N2+{N_{2}^{+}}

B

N2{N_{2} }

C

O2+{O_{2}^{+}}

D

O2{O_2}

Answer

N2+{N_{2}^{+}}

Explanation

Solution

N2⊕⇒  BO=2.5⇒[π−Bond−2&σ\-Bond=12]{ N_2^{\oplus} \Rightarrow \; BO = 2.5 \Rightarrow [ \pi - Bond - 2 \& \sigma \- Bond = \frac{1}{2} ]}
N2⇒  B.O.=3.0  ⇒[π−Bond=2&σ−Bond=1]{ N_2 \Rightarrow \; B.O. = 3.0 \; \Rightarrow [\pi - Bond = 2 \& \sigma - Bond = 1]}
O2⊕=B.O.⇒  2.5⇒[π−Bond=1.5&σ−Bond=1]{ O_2^{\oplus} = B.O. \Rightarrow \; 2.5 \Rightarrow [\pi-Bond = 1.5 \& \sigma-Bond = 1]}
O2⇒  B.O.⇒2⇒[π−Bond  ⇒1&σ−Bond=1]{ O_2 \Rightarrow \; B.O. \Rightarrow 2 \Rightarrow [\pi-Bond \; \Rightarrow 1 \& \sigma -Bond = 1]}