Solveeit Logo

Question

Physics Question on Photoelectric Effect

Two photons of energies twice and thrice the work function of a.metal are incident On the metal surface. Then the ratio of maximum velocities of the photoelectrons emitted in the two cases respectively is

A

2;1\sqrt{2};1

B

3;1\sqrt{3};1

C

3;2\sqrt{3};\sqrt{2}

D

1;21;\sqrt{2}

Answer

1;21;\sqrt{2}

Explanation

Solution

V1V2=E1ω0E2ω0\frac{V_1}{V_2} = \sqrt{\frac{E_1 - \omega_0}{E_2 - \omega_0}}