Question: Two perfectly identical wires kept under tension are in unison. When the tension in wire is increase...

Question

Two perfectly identical wires kept under tension are in unison. When the tension in wire is increased by 1% then on sounding them together 3 beats are heard in 2 seconds. Find the frequency of each wire –

Answer 1

Solution

n = $\frac { 1 } { 2 \ell }$

3 beats in 2 sec i.e. 1.5 beats in 1 sec.

n + 1.5 = $\frac { 1 } { 2 \ell }$ $\sqrt { \frac { 1.01 \mathrm {~T} } { \mathrm {~m} } }$

As tension is increased 10%

\ = $\sqrt { 1.01 }$ = 1.005 ̃ n = 300