Question
Question: Two perfect gases one is monoatomic and another diatomic at absolute temperatures T<sub>1</sub> and ...
Two perfect gases one is monoatomic and another diatomic at absolute temperatures T1 and T2 are mixed. There is no loss of energy. The temperature of mixture, if masses of molecules are m1 and m2 and the number of molecules in the gases are n1 and n2 respectively –
A
2T1+T2
B
5n1+3n25n1T1+3n2T2
C
3n1+5n23n1T1+5n2T2
D
T1T2
Answer
3n1+5n23n1T1+5n2T2
Explanation
Solution
n1(23KT1)+n2(25KT2)=n1(23KT′)+n2(25KT′)
3n1+5n23n1T1+5n2T2=T′