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Question

Physics Question on Kinetic molecular theory of gases

Two perfect gases at absolute temperatures T1T_1 and T2 T_2 are mixed. There is no loss of energy. The temperature of mixture of masses of molecules are m1 m_1 and m2 m_2 and the number of molecules in the gases are n1n_1 and n2n_2 respectively, is

A

T1+T22\frac{ T_1 + T_2 }{ 2 }

B

n1T1+n2T2n1+n2\frac{ n_1 T_1 + n_2T_2 }{ n_1 + n_2 }

C

n1T2+n2T1n1+n2\frac{ n_1 T_2 + n_2T_1 }{ n_1 + n_2 }

D

T1T2/n1n2 \sqrt{ T_1 T_2 / n_1n_2}

Answer

n1T1+n2T2n1+n2\frac{ n_1 T_1 + n_2T_2 }{ n_1 + n_2 }

Explanation

Solution

We know E = 32nkT\frac{3}{ 2} n kT
k =Boltzmann's constant
32n1kT1+32n2kT2=32(n1+n2)kT\therefore \frac{3}{ 2} n_1 k T_1 + \frac{3}{ 2} n_2 k T_2 = \frac{3}{ 2} (n_1 + n_2) k T
T = n1T1+n2T2n1+n2\frac{ n_1 T_1 + n_2T_2 }{ n_1 + n_2 }