Two pendulums have time periods T and 5T/4. They starts SHM... | Physics | SolveeIt | Solveeit

Today, August 18

Question

Two pendulums have time periods T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation ?

A

$45{}^\circ$

B

$90{}^\circ$

C

$60{}^\circ$

D

$30{}^\circ$

Answer

$90{}^\circ$

Explanation

Solution

When bigger pendulum of time period (5T/4) completes one vibration, the smaller pendulum will complete (5/4) vibrations. It means the smaller pendulum will be leading the bigger pendulum by phase T/4 second = $\pi /2$ rad $=90{}^\circ$