Question

Two pendulums have time periods T and 5T / 4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?

• A. 45$^{\circ}$
• B. 90$^{\circ}$
• C. 60$^{\circ}$
• D. 30$^{\circ}$

Answer 1

Answer: (B)

90$^{\circ}$

Answer 2

When bigger pendulum of time period (5T/4) completes one vibration, the smaller pendulum will complete (5/4) vibrations. It means the smaller pendulum will be leading the bigger pendulum by phase T/4 second= $\pi$/ 2 rad= 90$^{\circ}$.