Two pendulum have time period T and ( \frac{5T}{4} ) they st... | Physics | SolveeIt | Solveeit

Today, August 18

Question

Two pendulum have time period T and $\frac{5T}{4}$ they start SHM at the same time form the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation

A

${{45}^{o}}$

B

${{90}^{o}}$

C

60?

D

$~{{30}^{o}}$

Answer

${{90}^{o}}$

Explanation

Solution

When bigger pendulum of time period $(5T/4)$ completes one vibration, the smaller pendulum will complete $(5T/4)$ vibration. It means the smaller pendulum will be leading the bigger pendulum by phase $\frac{T}{4}s=\frac{\pi }{2}rad={{90}^{o}}.$