Question

Two particles of masses m and 2m and charges 2q and 2q are placed in a uniform electric field E and allowed to move for the same time. The ratio of kinetic energies will be –

• A. 2 : 1
• B. 8 : 1
• C. 4 : 1
• D. 1 : 4

Answer 1

Answer: (A)

2 : 1

Answer 2

$\frac { K E _ { A } } { K E _ { B } }$ = $\frac { 1 / 2 \mathrm {~m} _ { \mathrm { A } } \mathrm { v } _ { \mathrm { A } } ^ { 2 } } { 1 / 2 \mathrm {~m} _ { \mathrm { B } } \mathrm { v } _ { \mathrm { B } } ^ { 2 } }$

v_A = u_A + a_At

v_A = t

v_B = t

\ $\frac { K E _ { A } } { K E _ { B } }$ =