Question
Question: Two particles of mass MA and MB and their velocities are VA and VB respectively collide. After colli...
Two particles of mass MA and MB and their velocities are VA and VB respectively collide. After collision they interchange their velocities then MBMA is?
Solution
When two particles collide and there are no other forces acting on the particles, then we can use the concept of conservation of momentum.
Complete step by step solution:
Consider the Initial situation,
The body of mass MA is moving with speed VA, hence its initial momentum can be written as PAI= MAVA .
The body of mass MB is moving with speed VB, hence its initial momentum can be written as PBI= MBVB .
Hence total initial momentum of the system will be
PI= PAI+ PBI ,
Putting the values from above
PI= MAVA+ MBVB .
Consider the Final situation,
The body of mass MA is moving with speed VB, hence its final momentum can be written as PAF= MAVB .
The body of mass MB is moving with speed VA, hence its final momentum can be written as PBF= MBVA .
Hence total final momentum of the system will be
PF= PAF+ PBF ,
Putting the values from above
PF= MAVB+ MBVA .
By conservation of momentum,
PI=PF,
Putting the values from above,
MAVA+ MBVB= MAVB+ MBVA,
Taking MA and MB to different sides of the equation
MAVA− MAVB= MBVA−MBVB,
Taking MA and MB common on each side of the equation
MA(VA− VB)= MB(VA−VB),
Cancelling (VA−VB) gives
MA= MB,
i.e. MBMA=1 .
Note: Before attempting to solve the problem, the student needs to be able to understand that the conservation momentum is applicable whenever the external force on the system is not present. Another important equation that is used in questions of collision is of the coefficient of restitution, which is applicable for all types of collision, whether external forces are present on the system or not.