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Question

Physics Question on Centre of mass

Two particles of mass 5kg5\,kg and 10kg10\,kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg5\,kg particle is nearly at a distance of :

A

33 cm

B

50 cm

C

67 cm

D

80 cm

Answer

67 cm

Explanation

Solution

Let position of centre of mass be (xc.m,0){(x_{c.m}, 0)}
xcm=m1x1+m2x2m1+m2x_{cm}=\frac{m_{1}x_{1}+m_{2}x_{2}}{m_{1}+m_{2}}
=5×0+100×105+10=\frac{5 \times 0+100 \times 10}{5+10}
=2002=\frac{200}{2}
=66.66cm=66.66\,cm
xcm=67cmx_{cm}=67\,cm