Question

Two particles having position vectors $\vec{ r _{1}}=(3 \hat{ i }+5 \hat{ j }) m$ and $\vec{ r _{2}}=(-5 \hat{ i }-3 \hat{ j }) m$ are moving with velocities $\vec{ v _{1}}=(4 \hat{ i }+3 \hat{ j }) ms ^{-1}$ and $\vec{ v }_{2}=(a \hat{ i }+7 \hat{ j }) ms ^{-1}$. If they collide after $2\, s$, the value of $a$ is

• A. 2
• B. 4
• C. 6
• D. 8

Answer 1

Answer: (D)

8

Answer 2

The correct answer is D:8
$A B=\vec{r}=\vec{r_{1}}-\vec{r_{2}}$
$=(3 \hat{i}+5 \hat{j})-(-5 \hat{i}-3 \hat{j})$
$=(8 \hat{i}+8 \hat{j}) m$
$\vec{v}=\vec{v_{2}}-\vec{v_{1}}$
$=(a \hat{i}+7 \hat{j})-(4 \hat{i}+3 \hat{j})$
$=(a-4) \hat{i}+4 \hat{j}$
$\vec{v}=\frac{\vec{r}}{t}$
$(a-4) \vec{i}+\vec{4 j}=\frac{8 \hat{i}+8 \hat{j}}{2}$
$a=8$