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Question: Two particles are projected simultaneously in the same vertical plane, from the same point, both wit...

Two particles are projected simultaneously in the same vertical plane, from the same point, both with different speeds and at different angles with horizontal. The path followed by one, as seen by the other, is

A

A vertical line

B

A parabola

C

A hyperbola

D

A straight line making a constant angle (90o\neq 90^{o}) with horizontal

Answer

A straight line making a constant angle (90o\neq 90^{o}) with horizontal

Explanation

Solution

Let u1{\overset{\rightarrow}{u}}_{1}andu2{\overset{\rightarrow}{u}}_{2} be the initial velocities of the two particles and θ1\theta_{1}and θ2\theta_{2}be their angles of projections with the horizontal.

The velocities of the two particles after time t are

v1=(u1cosθ1)i^+(u1sinθ1gt)j^{\overset{\rightarrow}{v}}_{1} = (u_{1}\cos\theta_{1})\widehat{i} + (u_{1}\sin\theta_{1} - gt)\widehat{j}

And v2=(u2cosθ2)i^+(u2sinθ2gt)j^{\overset{\rightarrow}{v}}_{2} = (u_{2}\cos\theta_{2})\widehat{i} + (u_{2}\sin\theta_{2} - gt)\widehat{j}

Their relative velocity is

v12=v1v2{\overrightarrow{v}}_{12} = {\overset{\rightarrow}{v}}_{1} - {\overset{\rightarrow}{v}}_{2}

=(u1cosθ1u2cosθ2)i^+(u1sinθ1u2sinθ2)j^= (u_{1}\cos\theta_{1} - u_{2}\cos\theta_{2})\widehat{i} + (u_{1}\sin\theta_{1} - u_{2}\sin\theta_{2})\widehat{j}

Which is a constant. So the path followed by one, as seen by the other is straight line, making a constant angle with the horizontal.