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Question

Physics Question on projectile motion

Two particles are projected simultaneously in the same vertical plane, from the same point, both with different speeds and at different angles with horizontal. The path followed by one, as seen by the other, is

A

a vertical line

B

a parabola

C

a hyperbola

D

a straight line making a constant angle (90)\left(\ne 90^{\circ}\right) with horizontal

Answer

a straight line making a constant angle (90)\left(\ne 90^{\circ}\right) with horizontal

Explanation

Solution

Let u1\vec{u}_{1} and u2\vec{u}_{2} be the initial velocities of the two particles and θ1\theta_1 and θ2\theta_2 be their angles of projection with the horizontal. The velocities of the two particles after time tt are, v1=(u1cosθ1)i^+(u1sinθ1gt)j^\vec{v}_{1}=\left(u_{1}\,cos\,\theta_{1}\right)\hat{i}+\left(u_{1}\,sin\,\theta_{1}-gt\right)\hat{j} and v2=(u2cosθ2)i^+(u2sinθ2gt)j^\vec{v}_{2}=\left(u_{2}\,cos\,\theta_{2}\right)\hat{i}+\left(u_{2}\,sin\,\theta_{2}-gt\right)\hat{j} v12=v1v2\vec{v}_{12}=\vec{v}_{1}-\vec{v_{2}} =(u1cosθ1u2cosθ2)i^+(u1sinθ2u2sinθ2)j^=\left(u_{1}\,cos\,\theta_{1}-u_{2}\,cos\,\theta_{2}\right)\hat{i}+\left(u_{1}\,sin\,\theta_{2}-u_{2}\,sin\,\theta_{2}\right)\hat{j} which is a constant. So the path followed by one, as seen by the other is straight line, making a constant angle with the horizontal.