Question

Two particles are executing S.H.M. The equation of their motion are $y _ { 1 } = 10 \sin \left( \omega t + \frac { \pi T } { 4 } \right)$ $y_{2} = 25\sin\left( \omega t + \frac{\sqrt{3}\pi T}{4} \right)$. What is the ratio of their amplitude

• A. 1 : 1
• B. 2 : 5
• C. 1 : 2
• D. None of these

Answer 1

Answer: (B)

2 : 5

Answer 2

$\frac{a_{1}}{a_{2}} = \frac{10}{25} = \frac{2}{5}$