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Question: Two particles A and B initially at rest move towards each other under a mutual force of attraction. ...

Two particles A and B initially at rest move towards each other under a mutual force of attraction. At the instant when velocity of AA is vv and that of BB is 2v2v, the velocity of centre of mass of the system
(A)2v (B)zero (C)1.5v (D)v \begin{aligned} & \left( A \right)2v \\\ & \left( B \right)zero \\\ & \left( C \right)1.5v \\\ & \left( D \right)v \\\ \end{aligned}

Explanation

Solution

It is given that there is no external force hence no change in momentum of center of mass and it will remain zero. By the law of conservation of momentum, the momentum is zero. The initial velocity of the particles were 00 because both AA and BB were at rest.

Formula used:
F=maF=ma
Where:
mm= mass of particle
aa= acceleration

Complete step-by-step answer:
As given in problem that both the particles were at rest so at first, we calculate initial force on them:
Force FA{{F}_{A}}​ on particle AA is given by
FA=mAaA=mAvt...(1){{F}_{A}}={{m}_{A}}aA=\dfrac{{{m}_{A}}v}{t}...\left( 1 \right)
Similarly FB=mBaB=mB(2v)t...(2){{F}_{B}}={{m}_{B}}{{a}_{B}}=\dfrac{{{m}_{B}}\left( 2v \right)}{t}...\left( 2 \right)
Now:
mAvt=mB(2v)t(FA=FB)\dfrac{{{m}_{A}}v}{t}=\dfrac{{{m}_{B}}\left( 2v \right)}{t}(\because FA=FB)
So,
 mA=2mB~{{m}_{A}}=2{{m}_{B}}
For the centre of mass of the system
v=mAvA+mBvBmA+mBv=\dfrac{{{m}_{A}}{{v}_{A}}+{{m}_{B}}{{v}_{B}}}{{{m}_{A}}+{{m}_{B}}}
or
 v=2mBvmB×2v2mB+mB=0~v=\dfrac{2{{m}_{B}}v-{{m}_{B}}\times 2v}{2{{m}_{B}}+{{m}_{B}}}=0
Here we use negative signs because the particle is travelling in the opposite direction.

So, the correct answer is “Option B”.

Additional Information:
Law of conservation of momentum states that two or more bodies in an isolated system acting upon one another, their total momentum remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed. Some examples of law of conservation of momentum: Air-filled balloons, System of gun and bullet, Motion of rockets.
The law of conservation of momentum is a crucial consequence of Newton’s third law of motion.

Note: Alternatively, if we consider the 2 masses during a system then no external force is acting on the system. Mutual forces are internal forces. Since the centre of mass is initially at rest, it will be at rest until no external force applied on it.