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Question

Physics Question on System of Particles & Rotational Motion

Two particles AA and BB are moving as shown in the figure. Their total angular momentum about the point OO is

A

9.8 kg m2/sm^2/s

B

Zero

C

52.7 kg m2/sm^2/s

D

37.9 kg m2/sm^2/s

Answer

9.8 kg m2/sm^2/s

Explanation

Solution

Total angular momentum about OO is given as,
L=L1+L2=m1v1r1+m2v2r2L = L _{1}+ L _{2}=m_{1} v_{1} r_{1}+m_{2} v_{2} r_{2}
=6.5×2.2×1.5+3.1×3.6×2.8=-6.5 \times 2.2 \times 1.5+3.1 \times 3.6 \times 2.8
=21.45+31.248=9.8kgm2/s=-21.45+31.248=9.8\, kgm ^{2} / s