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Question: Two partials are thrown horizontally in opposite directions from the same point from a height h with...

Two partials are thrown horizontally in opposite directions from the same point from a height h with velocities 4 ms-1 and 3ms-1. Find the separation between them when their velocities are perpendicular .

A

0.15 s

B

0.25 s

C

0.35 s

D

None of these

Answer

0.35 s

Explanation

Solution

V1=4i^gtj^{\overrightarrow{V}}_{1} = - 4\widehat{i} - gt\widehat{j} and V2=3i^gtj^{\overrightarrow{V}}_{2} = 3\widehat{i} - gt\widehat{j} are the velocities at any instant. For velocities to be perpendicular V1.V2{\overrightarrow{V}}_{1}.{\overrightarrow{V}}_{2} = 0

that is V1.V2{\overrightarrow{V}}_{1}.{\overrightarrow{V}}_{2} = 0 or t = 12/g2\sqrt{12/g^{2}} = 0.35 s

separation = (u1 + u2)t = 7(0.35) = 2.45 m.