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Question

Question: Two parallel wires 2 m apart carry currents of 2 A and 5 A respectively in same direction, the force...

Two parallel wires 2 m apart carry currents of 2 A and 5 A respectively in same direction, the force per unit length acting between these two wires is

A

2 × 10-6 N m-1

B

3 × 10-6 N m-1

C

1 × 10-6 N m-1

D

4 × 10-6 N m-1

Answer

1 × 10-6 N m-1

Explanation

Solution

Given I1=2 A,I2=5 A,r=2 m\mathrm { I } _ { 1 } = 2 \mathrm {~A} , \mathrm { I } _ { 2 } = 5 \mathrm {~A} , \mathrm { r } = 2 \mathrm {~m}

f=μ04π2I1I2r=107×2×2×52=1×106Nm1\therefore \mathrm { f } = \frac { \mu _ { 0 } } { 4 \pi } \frac { 2 \mathrm { I } _ { 1 } \mathrm { I } _ { 2 } } { \mathrm { r } } = 10 ^ { - 7 } \times \frac { 2 \times 2 \times 5 } { 2 } = 1 \times 10 ^ { - 6 } \mathrm { Nm } ^ { - 1 }