Question

Two parallel plates have equal and opposite charge. When the space between them is evacuated, the electric field between the plates is $2 \times 10^{5}V/m$. When the space is filled with dielectric, the electric field becomes$1 \times 10^{5}V/m$. The dielectric constant of the dielectric material

• A. 1/2
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (C)

2

Answer 2

$K = \frac{E_{\text{without dielectric }}}{E_{\text{with dielectric}}} = \frac{2 \times 10^{5}}{1 \times 10^{5}} = 2$

($K = \frac{E_{fuokZr\ }}{E_{ijkoS?kqr\ lfgr}} = \frac{2 \times 10^{5}}{1 \times 10^{5}} = 2$)