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Question

Physics Question on Electrostatic potential

Two parallel plates are separated by 2cm2\,cm. If the potential difference between them be 20V20\,V, then electric field between them is :

A

100 NC1NC^{-1}

B

200 NC1NC^{-1}

C

1000 NC1NC^{-1}

D

2000 NC1NC^{-1}

Answer

1000 NC1NC^{-1}

Explanation

Solution

E=V/dE = V/d = 20 VV/0.02 m = 1000 V.