Solveeit Logo

Question

Question: Two parallel plate capacitors of capacitance C and 3C are connected in parallel and charged to a pot...

Two parallel plate capacitors of capacitance C and 3C are connected in parallel and charged to a potential difference V with the help of a battery. The battery is disconnected and the space between these two capacitors are filled with dielectric of constant K and K/2 respectively. The voltage across the combination will be-

A

B

6 V3 K\frac { 6 \mathrm {~V} } { 3 \mathrm {~K} }

C

8 V5 K\frac { 8 \mathrm {~V} } { 5 \mathrm {~K} }

D

3 V5 K\frac { 3 \mathrm {~V} } { 5 \mathrm {~K} }

Answer

8 V5 K\frac { 8 \mathrm {~V} } { 5 \mathrm {~K} }

Explanation

Solution

Common potential = q1+q2C1+C2\frac { \mathrm { q } _ { 1 } + \mathrm { q } _ { 2 } } { \mathrm { C } _ { 1 } + \mathrm { C } _ { 2 } } = CV+3CVKC+K23C\frac { \mathrm { CV } + 3 \mathrm { CV } } { \mathrm { KC } + \frac { \mathrm { K } } { 2 } 3 \mathrm { C } }

= =