Question
Question: Two parallel metal plates carry charges +Q and – Q respectively. A test charge q<sub>0</sub> placed ...
Two parallel metal plates carry charges +Q and – Q respectively. A test charge q0 placed between them experiences a force F. Now the separation between the plates is doubled, then the force on the test charge will be –
A
F
B
2F
C
F/2
D
F/4
Answer
F
Explanation
Solution
Initially force on charge q0 is
F = q0(2E) = 2q0E
If separation between the plates is doubled E= same
\ F = same