Question
Question: Two parallel infinite line charges \( + \lambda \) and \( - \lambda \) are placed with a separation ...
Two parallel infinite line charges +λ and −λ are placed with a separation distance R in free space. The net electric field exactly midway between the two line charges is
(A) Zero
(B) πE0R2λ
(C) πE0Rλ
(D) 2πE0R1
Solution
The direction can be identified by seeing the distance or separation between the charges as: At exactly midway so the distance can be exactly half so here, the parallel infinite charges both positive and negative charges mean in the same direction.
Formula used:
Different formulas will be used to solve the problem which is mentioned below as:
E1=2πE02Rλ E2=2πE02R−λ
Where R is distance between the separation
E0 Is epsilon value
E is the electrical field
λ Is the positive and negative both are the infinite line charge
Complete Step by step answer:
As we know that a point charge is a hypothetical charge located at a single point in space.
And then the electric field is a vector. There are multiple point charges present. The net electric field at any point is the vector sum of the electric fields due to the individual charges.
By this image we can understand that separation R so as it’s at its exactly midway so we can take 2R as their mid separation and this both the charges are in same direction
As parallel is given so both the direction will be same let be left to right
E1=2πE02Rλ and E2=2πE02R−λ
So, the net energy is,
Enet=E1+E2
Enet=2πE02Rλ+2πE02R−λ
⇒Enet=πE0R2λ So we get,
Hence the net electric field is: Enet=πE0R2λ
Hence the correct option is B that is πE0R2λ.
Note:
In question probably we get the hint so first we need to think about the direction of the charges. And then what is the distance of separation between the charges.
So first basically the electric field of an individual and then to get a total combining electric fields of the charges.